Question

As shown in the figure below, Justin walks from the house to his truck on a windy day. He walks 20 m toward

the truck, 15 m back to retrieve his wind-blown hat, and another 20 m to reach the truck. He walked a total
time of 75 s.
What is Justin’s average velocity over the 75 s period? What is Justin’s average speed over the 75 s period?
Round answers to two significant digits.
Answer using coordinate system where rightward is positive.

Answer 1

Complete Question

The complete question is shown on the first uploaded image

Answer:

The velocity is
`v =0.333 \  m/s` in positive x -direction

The speed is
`s = 0.733 \ m/s`

Step-by-step explanation:

From the question we are told that

The distance from the house to truck is D = 20 m

The distance traveled back to retrieve wind-blown hat is d = 15

The distance from the wind-blown hat position too the truck is k = 20 m

The total time taken is t = 75 s

Generally when calculating the displacement the Justin's backward movement to collect his wind - blown hat is taken as negative

Generally Justin's displacement is mathematically represented as

`L = 20 - 15 + 20`

=>
`L  =  25 \ m`

Generally the average velocity is mathematically represented as

`v = (L)/(t)`

=>
`v = (25)/(75)`

=>
`v =0.333 \  m/s`

Generally the distance covered by Justin is mathematically represented as

`R = D+ d + k`

=>
`R = 20 + 15 +20`

=>
`R =  55 \  m`

Generally Justin's average speed over a 75 s period is mathematically represented as

`s = (R)/( t)`

=>
`s = (55)/( 75)`

=>
`s = 0.733 \ m/s`