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(k³+8k²+10k+21)÷(k+7)​

(k³+8k²+10k+21)÷(k+7)​
26.7k views
3 votes
(k³+8k²+10k+21)÷(k+7)​

User Craig Myles
by
7.8k points

1 Answer

2 votes

Answer:

k^2 + k +3

Explanation:

User Matthew Gunn
by
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