Question

The temperature of a sample of water from the faucet increases from 22.7°C to 48.9°C when 3,710J are applied through electric shock. What is the mass of the sample of water? *DO NOT put units in your answer.**

Please help guys

Answer 1

33.8.

Step-by-step explanation:

Hello,

In this case, since the used equation is:

`Q=mCp(T_2-T_1)`

Whereas the specific heat is 4.184 J/(g°C), we compute the mass as follows:

`m=(Q)/(Cp(T_2-T_1))`

Thus, the mass turns out:

`m=(3,710J)/(4.184(J)/(g\°C) (48.9-22.7)\°C)\\\\m=33.8g`

And without units:

33.8.

Best regards.