Question

PRECALCULUS please help​

Answer 1

`( f - g)(x) = (2x - √(x) + 14 )/(3x)`

Explanation:

`f(x) = (2x + 6)/(3x) \\ \\ g(x) = ( √(x) - 8)/(3x)`

To find ( f - g)(x) , subtract g(x) from f(x)

That's

`( f - g)(x) = (2x + 6)/(3x) - ( √(x) - 8)/(3x)`

Since they have a common denominator that's 3x we can subtract them directly

That's

`(2x + 6)/(3x) - ( √(x) - 8)/(3x) = (2x + 6 - ( √(x) - 8) )/(3x) \\ = (2x + 6 - √(x) + 8 )/(3x) \\ = (2x - √(x) + 6 + 8 )/(3x)`

We have the final answer as

`( f - g)(x) = (2x - √(x) + 14 )/(3x)`

Hope this helps you