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Given t(x)=-4.9t2+3t+10, what is the value of t(1)?
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Given t(x)=-4.9t2+3t+10, what is the value of t(1)?

User HcgRandon
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1 Answer

3 votes

Explanation:

t(x) = -4.9t² + 3t + 10

t(1) = -4.9(1²) + 3(1) + 10

= -4.9 + 3 + 10

= 8.1

User Oktapodi
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