2 Answers

Frow · Answer 1 · 2021-10-26T08:50:49+0000

Answer:

h^(-1) (x) =
(2)/(3) x + 11

Explanation:

let y = h(x) and rearrange making x the subject , that is

y =
(3)/(2) (x - 11 ) ← multiply both sides by 2 to clear the fraction

2y = 3(x - 11) ← distribute

2y = 3x - 33 ( add 33 to both sides )

2y + 33 = 3x ( divide all terms by 3 )

(2)/(3) y + 11 = x

Change y back into terms of x with x =
h^(-1) (x) , thus

h^(-1) (x) =
(2)/(3) x + 11

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