Question

Please help.
This is very hard to me.

Answer 1

Width is 20 inches.

Length is 44 inches.

Explanation:

Recall that the perimeter of a rectangle is given by the formula:

`P=2(l+w)`

Where l is the length and w is the width.

We know that the length is 4 more than double the width. In other words, we can write an equation for l:

`l=4+2w`

Let's substitute this into the above equation. So:

`P=2((4+2w)+w)`

Combine like terms:

`P=2(4+3w)`

We are given that the perimeter is 128 (inches). So, substitute 128 for P and solve for w:

`128=2(4+3w)`

Divide both sides by 2. The right side cancels:

`64=4+3w`

Subtract 4 from both sides:

`3w=60`

Divide both sides by 3:

`w=20`

Therefore, our width is 20.

We can use the length formula we acquired previously to acquire length. We have:

`l=4+2w`

Substitute 20 for w:

`l=4+2(20)`

Multiply:

`l=4+40`

Add:

`l=44`

So, our length is 44.

And we width is 20.

And we're done!