Question

Suppose 6 pints of a 28% alcohol solution is mixed with 4 pints of a 90% alcohol solution. What is the concentration of alcohol in the new 10-pint mixture?

The concentration of alcohol in the new 10-pint mixture is 3%.

Answer 1

52.8%

Explanation:

The amount of alcohol is:

0.28 (6 pints) + 0.90 (4 pints) = 5.28 pints

So the concentration is:

5.28 pints / 10 pints × 100% = 52.8%.