Question

35. A daredevil is launched out of a

cannon with an initial horizontal
velocity of 30 m/s. If it took a total
of 13 s for the daredevil to land in
the safety net, how far was the fall
during the flight?

Answer 1

845 m

Step-by-step explanation:

Given in the y direction:

v₀ = 0 m/s

a = 10 m/s²

t = 13 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (13 s) + ½ (10 m/s²) (13 s)²

Δy = 845 m