Question

A cargo ship initially traveling at 14.1 m/s slows down uniformly and

comes to rest over a distance of 1.60 km (1,600 m). The average
acceleration of the cargo ship is m/s.

Answer 1

-0.0621 m/s²

Step-by-step explanation:

Given:

Δx = 1600 m

v₀ = 14.1 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (14.1 m/s)² + 2a (1600 m)

a = -0.0621 m/s²