Question

If an airplane descends 15 feet every 1.45 seconds, how far would the airplane travel in three and a half minutes? The equation is y=-40x+58

Answer 1

`\qquad\qquad\huge\underline{{\sf Answer}}`

Here we go ~

The air plane descends 15 feels every 1.45 seconds, so it's unit rate is :

`\qquad \sf  \dashrightarrow \: (15)/(1.45) \: \: ft / sec`

Now we have to calculate the descent in 3.5 minutes ~

`\qquad \sf  \dashrightarrow \: (15)/(1.45) \: \: * 3.5 * 60`

`\qquad \sf  \dashrightarrow \: 2172.41 \: \: ft`

So, the airplane descends 2172.41 feels in three and a half minutes ~