If an airplane descends 15 feet every 1.45 seconds, how far would the airplane travel in three and a half minutes? The equation is y=-40x+58

Question

asked Oct 27, 2023 165k views

1 Answer

Borgr · Answer 1 · 2023-11-01T04:53:19+0000

$\qquad\qquad\huge\underline{{\sf Answer}}$

Here we go ~

The air plane descends 15 feels every 1.45 seconds, so it's unit rate is :

$\qquad \sf  \dashrightarrow \: (15)/(1.45) \: \: ft / sec$

Now we have to calculate the descent in 3.5 minutes ~

$\qquad \sf  \dashrightarrow \: (15)/(1.45) \: \: * 3.5 * 60$

$\qquad \sf  \dashrightarrow \: 2172.41 \: \: ft$

So, the airplane descends 2172.41 feels in three and a half minutes ~