Question

What is the distance between J(5.4,-3.2) and K(4,-1.2)

Answer 1

The answer is

2.44 units

Explanation:

The distance between two points can be found by using the formula

`d = \sqrt{ ({x1 - x2})^(2) + ({y1 - y2})^(2) } \\`

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

J(5.4,-3.2) and K(4,-1.2)

The distance between them is

`|JK| = \sqrt{ ({5.4 - 4})^(2) + ({ - 3.2 + 1.2})^(2) } \\ = \sqrt{( {1.4})^(2) + ({ - 2})^(2) } \\ = √(1.96 + 4) \\ = √(5.96) \: \: \: \: \: \: \: \: \\ = 2.44131112`

We have the final answer as

2.44 units

Hope this helps you