Explanation:
2. The number of ways to choose 2 people from a group of 4 (where the order doesn't matter) is ₄C₂.
The number of ways to choose 2 people from a group of 3 (not including Jason) is ₃C₂.
So the probability is ₃C₂ / ₄C₂ = 3/6 = 1/2.
3. If Damian has already been selected, then the probability that J.T. will be selected from the remaining 8 is 1/8.
4. This question is oddly worded. The sales and marketing teams will be equally represented on average. If many pairs are selected and replaced, sales will be selected 4/9 of the time, and marketing will be selected 5/9 of the time. However, for any particular pair, the representation will not be proportional.