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14. Find the value of x if QS bisects PQR and
mZPQR = 82.
(10.x + 1)
S
R

14. Find the value of x if QS bisects PQR and mZPQR = 82. (10.x + 1) S R-example-1
User Homer Xing
by
6.2k points

1 Answer

2 votes

Answer:

x = 4

Explanation:

Since, QS bisects
\angle PQR.


\therefore m\angle PQS = (1)/(2) * m\angle PQR\\</p><p>\therefore (10x + 1)\degree = (1)/(2) * 82\degree \\</p><p>\therefore (10x + 1)\degree = 41\degree \\</p><p>\therefore 10x + 1 = 41 \\</p><p>\therefore 10x = 41 - 1\\</p><p>\therefore 10x = 40\\</p><p>\therefore x = (40)/(10) \\</p><p>\huge \orange {\boxed {\therefore x = 4}}

User Cal Jacobson
by
6.8k points
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