Question

A sample of seawater has 0.075 g of sodium chloride per mL of solution. How many moles of sodium chloride are there per liter of this solution?

Answer 1

1.28 mol

Step-by-step explanation:

mole = mass/molar mass

n = v/v/cm³

mass = 0. 075g

v = 1dm³ =1000cm³

n= m/MV=0.075/58.44(1000)

n =1.28 mol