Question

Help with this pleaseeee​

Answer 1

(- 3, 37) and (-
`(5)/(2)`,
`(63)/(2)` )

Explanation:

Given the 2 equations

2x² - y + 19 = 0 → (1)

y + 11x = 4 → (2) ← subtract 11x from both sides

y = 4 - 11x → (3)

Substitute y = 4 - 11x into (1)

2x² - (4 - 11x) + 19 = 0

2x² - 4 + 11x + 19 = 0

2x² + 11x + 15 = 0 ← in standard form

(2x + 5)(x + 3) = 0 ← in factored form

Equate each factor to zero and solve for x

2x + 5 = 0 ⇒ 2x = - 5 ⇒ x = -
`(5)/(2)`

x + 3 = 0 ⇒ x = - 3

Substitute these values into (3) for corresponding values of y

x = -
`(5)/(2)` : y = 4 +
`(55)/(2)` =
`(63)/(2)` ⇒ (-
`(5)/(2)`,
`(63)/(2)` )

x = - 3 : y = 4 + 33 = 37 ⇒ (- 3, 37 )