Question

B is between line AC. If AB = x^2– 3x, BC = 9x, and AC = 16. Solve for x.

Answer 1

x = {- 8, 2}

Explanation:

Since, B is between line AC.

`\therefore AB + BC = AC\\</p><p>\therefore x^2 - 3x + 9x = 16\\</p><p>\therefore x^2 - 3x + 9x - 16=0\\</p><p>\therefore x^2 + 6x - 16=0\\</p><p>\therefore x^2 + 8x - 2x- 16=0\\</p><p>\therefore x(x +8) - 2(x + 8)=0\\</p><p>\therefore (x+8)(x-2)=0\\</p><p>\therefore x + 8 = 0\: or \: x-2=0\\</p><p>\therefore x = - 8 \:or\: x = 2\\</p><p>\huge \orange {\boxed {\therefore x = \{-8,\: 2\}}}`