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Find the following for the function f(x) = 3x2 + 4x - 4.

(a) f(0)
(e) - f(x)
(b) f(3)
(f) f(x+3)
(c) f(-3)
(g) f(3x)
(d) f(-x)
(h) f(x+h)
(a) f(0) = (Simplify your answer.)
(b) f(3) = (Simplify your answer.)
(c) f(-3)=(Simplify your answer.)

User Raunaqss
by
8.0k points

1 Answer

5 votes

Final answer:

To find f(0), f(3), and f(-3) for the function f(x) = 3x^2 + 4x - 4, substitute the values of x into the function and simplify to get f(0) = -4, f(3) = 35, and f(-3) = 11.

Step-by-step explanation:

To find values of the function f(x) = 3x2 + 4x - 4, we simply substitute the given x values into the equation and simplify.

f(0)

Substitute x = 0 into the function:

f(0) = 3(0)2 + 4(0) - 4

f(0) = -4 (as the x terms all drop away)

f(3)

Substitute x = 3 into the function:

f(3) = 3(3)2 + 4(3) - 4

f(3) = 3(9) + 12 - 4

f(3) = 27 + 12 - 4

f(3) = 35

f(-3)

Substitute x = -3 into the function:

f(-3) = 3(-3)2 + 4(-3) - 4

f(-3) = 3(9) - 12 - 4

f(-3) = 27 - 12 - 4

f(-3) = 11

User Betteroutthanin
by
8.3k points

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