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On the asteroid Cere, the acceleration due to gravity is about 0.27 m/s^2. How long would it take a ball to fall to the ground if dropped from a height of 90 m?

Answer Choices: A. 30.77s B. 28.4s C. 27,12s D. 29.79s E. 31.84s F. 25.82s

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Answer:

F. 25.82 s

Step-by-step explanation:

Given:

Δy = 90 m

v₀ = 0 m/s

a = 0.27 m/s²

Find: t

Δy = v₀ t + ½ at²

90 m = (0 m/s) t + ½ (0.27 m/s²) t²

t = 25.82 s

User Nitsan Wakart
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