Question

Write an equation of the line passes through the given points (6,-3),(1,2)

Answer 1

y = -x + 3

`m = (y_(1) - y_(2) )/(x_(1) - x_(2))`

`m = (6 - 1 )/(-3 - 2)`

`m = (5 )/(-5)`

`m=-1`

y = mx + b

substitute

2 = -1(1) + b

2 = -1 + b

3 = b

Answer 2

y = -x+3

Explanation:

First find the slope

m = ( y2-y1)/(x2-x1)

= ( 2 - -3)/( 1 - 6)

( 2+3)/( 1-6)

5/ -5

-1

The slope is -1

We can use slope intercept form

y = mx+b where m is the slope and b is the y intercept

y = -x+b

Substitute a point into the equation

2 = -1 +b

Add 1 to each side

2+1 = -1+1+b

3 = b

y = -x+3