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1 vote
I could really use some help , ive never done this before .:,)

I could really use some help , ive never done this before .:,)-example-1

1 Answer

3 votes

Answer:

Step-by-step explanation: This is what i can do

1. The first graph belongs to this question


3p+4\geq -14 , 1-5p\geq -39\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:3y+4\ge \:-14:\quad y\ge \:-6\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:1-5y\ge \:-39:\quad y\le \:8\\\\=\begin{bmatrix}y\ge \:-6\\ y\le \:8\end{bmatrix}\\\\\mathrm{1.\:Graph\:each\:inequality\:separately.}\\\mathrm{2.\:Choose\:a\:test\:point\:to\:determine\:which\:side\:of\:the\:line\:needs\:to\:be\:shaded.}\\


3.\:The\:solution\:to\:the\:system\:, will\:be\\\:the\:area\:where\:the\:shadings\:from\:each\:\\inequality\:overlap\:one\:another.\\\\\mathrm{See\:graph\:below.}\\\\\begin{bmatrix}y\ge \:-6\\ y\le \:8\end{bmatrix}\quad \mathrm{Unbounded}

I could really use some help , ive never done this before .:,)-example-1
User Clockworknet
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