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Find the value of y for which the value of 8y+3 is 7 more than the value of 6y

User Jbryson
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1 Answer

5 votes
Answer: y=2

Explanation:
Since 8y+3 is 7 more than 6y, you would write your equation like this:
8y+3=6y+7
Next, you would subtract 3 from both sides to get:
8y=6y+4
Now, you subtract 6y from both sides to get:
2y=4
Lastly, you divide both sides by 2 to get:
y=2
Hope this helps!
User Bill Stidham
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