102k views
3 votes
When 1.20 moles of MgO reacts as completely as possible with 0.900 moles of NaCl, the total number of moles of reaction products is:

MgO (s) + 2 NaCl (aq) → MgCl2 (aq) + Na2O (aq)

User Mialkin
by
7.0k points

1 Answer

2 votes

Answer:

Step-by-step explanation:

limiting reactant is NaCl it is consumed completely)

calculate n for each product

n NaCl (mole ) n MgCl2(mole )

2 1

0.9 x

x = 0.45 mole

n NaCl n Na2O

2 1

0.900 x

x = 0.45 mole

the total number of moles of reaction products is: 0.45 + 0.45= 0.9mol

User Aravindh S
by
7.9k points

Related questions

asked Jul 17, 2018 190k views
Jwg asked Jul 17, 2018
by Jwg
8.0k points
1 answer
1 vote
190k views
asked Dec 13, 2022 52.0k views
Rowe asked Dec 13, 2022
by Rowe
8.6k points
1 answer
16 votes
52.0k views