Question

Use the distance formula to find the distance between each pair of points. Round your answers to the nearest hundredths place W (-3,-5) and T (2,-2)

Answer 1

√34

Explanation:

`W (-3,-5) =(x_1,y_1)\\T (2,-2)=(x_2,y_2)\\\\d = √(\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2)\\\\d=√(\left(2-\left(-3\right)\right)^2+\left(-2-\left(-5\right)\right)^2)\\\\d=√(\left(2+3\right)^2+\left(-2+5\right)^2)\\\\d=√(5^2+3^2)\\\\d=√(25+9)\\\\d=√(34)`

Answer 2

The answer is

5.83 units

Explanation:

The distance between two points can be found by using the formula

`d = \sqrt{ ({x1 - x2})^(2) + ({y1 - y2})^(2) } \\`

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

W (-3,-5) and T (2,-2)

The distance between them is

`|WT| = \sqrt{ ({ - 3 - 2})^(2) + ( { - 5 + 2})^(2) } \\ = \sqrt{ ({ - 5})^(2) + ( { - 3})^(2) } \: \: \: \\ = √(25 + 9) \\ = √(34) \: \: \: \: \: \: \: \: \\ = 5.830951`

We have the final answer as

5.83 units to the nearest hundredth

Hope this helps you