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How many moles of KBr are in a 25.5 grams sample of KBr?

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Hello there! :)


\huge\boxed{0.214mol}

Atomic mass of KBr = 39.098 (K) + 79.904 (Br) = 119.002 grams.

Convert from grams to moles using dimensional analysis. Use the provided

amount of grams in the sample to begin:


25.5 g * (1 mol)/(119.002g) = (25.5)/(119.002) = 0.214 mol

Therefore, there are approximately 0.214 moles of KBr in a 25.5 gram sample.

User Nachik
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