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Khadreal · Answer 1 · 2021-08-17T15:57:49+0000

Answer:

H₃O⁺.

Step-by-step explanation:

Hello,

In this case, ionization of ethanol yields hydrogen cations and ethoxide anions as follows:

$CH_3COOH+H_2O\rightleftharpoons H_3O^++CH_3COO^-$

Which is at equilibrium as ethanol is a weak acid. Thus, since the conjugate acid is formed by the outgoing H⁺ and the water, we say that the conjugate acid is then the hydroxonium ion, H₃O⁺ whereas the conjugate base is the remaining anion CH₃COO⁻.

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