Answer:
4x^2 + 4x + 1=9
4x^2 + 4x - 8=0
Dividing both sides by 4
x^2 + x -2=0
It can be written as
x^2 + 2x - x - 2=0
x(x+2) -1(x+2)=0
taking (x+2) as common on LHS
Then, (x+2)(x-1)=0
Now first equate x+2=0 ie x=-2
then x-1=0 ie x=1
Therefore, x has two values(roots)
that is -2,1