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If the volume of a cone is 10 m^3 what is its height if the area of the base is 10 m^2?

User Aristotle
by
8.3k points

2 Answers

4 votes

Answer:

height: 3 meter

Step-by-step explanation:


\sf volume : (1)/(3) \ x \ base \ area \ x \ height

Here given:

  • base area: 10 m²
  • height: h
  • volume: 10 m³

Solve:


\longrightarrow \sf 10 = (1)/(3) \ x \ 10 \ x \ h


\longrightarrow \sf 10 = (10)/(3) \ x \ h


\longrightarrow \sf (10 \ x \ 3)/(10) = h


\longrightarrow \sf 3 = h

User Arian Sharifian
by
8.3k points
8 votes

Answer:

3 m

Step-by-step explanation:


\textsf{Volume of a cone}=\sf (1)/(3) b h \quad\textsf{(where b is the area of the circular base and h is the height)}

Given:

  • volume = 10 m³
  • Area of base = 10 m²


\implies \sf 10=(1)/(3) \cdot 10 \cdot h


\implies \sf 10=(10)/(3)h


\implies \sf 30=10h


\implies \sf h=(30)/(10)=3

User Ezombort
by
7.3k points

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