Calculate the number of joules released when 75.0 grams of water are cooled from 100.0°C to 27.5°C

asked Mar 4, 2023 169k views

7 votes

Calculate the number of joules released when 75.0 grams of water are cooled from

100.0°C to 27.5°C

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13 votes

Answer:

-22750.5J or -2.28× 10⁴J

Step-by-step explanation:

q=(75.0g)(4.184J)(27.5°C-100.0°C)

q= -22750.5J

q= -2.28× 10⁴J

Junkdog answered Mar 11, 2023

4.6k points

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