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Factor completely 16a^3b^7 + 2a^6b^4 - 22a^4b^5
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Factor completely 16a^3b^7 + 2a^6b^4 - 22a^4b^5

User Artur Iwan
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1 Answer

2 votes

Answer:


2a^3b^4(8b^3+a^3-11ab)

Explanation:


as^3b^4(8b^3) +2a^6b^4-22a^4b^5\\2a^3b^4(8b^3)+2a^3b^4(a^3)-22a^4b^5\\2a^3b^4(8b^3)+2a^3b^4(a^3)+2a^3b^4(-11ab)\\2a^3b^4(8b^3+a^3)+2a^3b^4(-11ab)\\2a^3b^4(8b^3+a^3-11ab)

User Mikaelblomkvistsson
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