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Write the equation of the line that passes through (-3,6) with a slope of -2

User Mike Lutz
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\diamond\large\blue\textsf{\textbf{\underline{Given question:-}}}

What is the equation of the line that passes through (-3, 6) and has a slope of -2?


\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}\diamond

First, we need to write the equation of the line in point-slope form:-


\sf{y-y_1=m(x-x_1)}

Replace y1 with 6, m with -2, and x1 with -3:-


\sf{y-6=-2(x-(-3)}

On simplification,


\sf{y-6=-2(x+3)}

On further simplification,


\sf{y-6=-2x-6}

Add 6 on both sides:-


\it{y=-2x}

Good luck with your studies.

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User Michalduda
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