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Geometry help plspls pls pls pls pls

Geometry help plspls pls pls pls pls-example-1
User Rigon
by
4.3k points

1 Answer

3 votes

Answer:

x = - 2.5, 1

Explanation:

In the given figure, JM and JK are the tangents drawn from the external point J to the
\odot L, Points K and M are points of tangency.

Since, tangents drawn from external point to a circle are congruent.


\therefore JM = JK\\\therefore 2x^2 +3x - 2 = 3\\\therefore 2x^2 +3x - 2 -3=0\\\therefore 2x^2 +3x - 5 =0\\\therefore 2x^2 - 2x + 5x - 5 =0\\\therefore 2x(x - 1) + 5(x - 1) =0\\\therefore (x - 1) (2x+ 5) =0\\\therefore x - 1 = 0\: or \: 2x + 5= 0\\\therefore x = 1\: or \:2x = - 5\\\therefore x = 1\: or \:x = - 2.5\\\huge \purple {\boxed {\therefore x = \{-2.5,\: 1\}}}

User Erdos
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4.6k points