Question

13x^2-16x=x^2-x

Can someone help solve this in using the quadratic formula

Answer 1

Explanation:

Answer 2

x₁ = ⁵/₄ , x₂ = 0

Explanation:

`13x^2-16x=x^2-x\\\\13x^2-16x-x^2+x=0\\\\12x^2-15x=0\\{\qquad}^(/3)\qquad\quad^(/3)\\4x^2-5x=0\quad\implies\quad a=4\,,\ b=-5\,,\ c=0\\\\\\x=(-b\pm√(b^2-4ac))/(2a)=(-(-5)\pm√((-5)^2-4\cdot4\cdot0))/(2\cdot4)=\frac{5\pm√(25)}8\\\\\\x_1=\frac{5+5}8=\frac54\,,\qquad x_2=\frac{5-5}8=0`