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5 votes
1. Carter will install fencing all around the flat area of his

backyard. Determine the amount of fencing he needs to the
nearest whole yard,

1. Carter will install fencing all around the flat area of his backyard. Determine-example-1
User Swineone
by
4.9k points

2 Answers

1 vote

Answer:

75 yards

Explanation:

User Perry Monschau
by
5.4k points
4 votes

Answer:

Amount of fencing required = 75 yards

Explanation:

Distance between the two points
(x_1,y_1) and
(x_2,y_2) is given by the formula,

d =
√((x_2-x_1)^2+(y_2-y_1)^2)

Distance between A(3, 6) and B(3, -2) =
√((3-3)^2+(6+2)^2)

= 8 yards

Distance between B(3, -2) and C(-7, 4) =
√((3+7)^2+(-2-4)^2)

=
√(136)

= 11.66 ≈ 12 yards

Distance between C(-7, 4) and D(-7, -2) =
√((-7+7)^2+(4+2)^2)

= 6 yards

Distance between D(-7, -2) and E(-3, -2) =
√((-7+3)^2+(-2+2)^2)

= 4 yards

Distance between E(-3, -2) and F(-3, -8) =
√((-3+3)^2+(-2+8)^2)

= 6 yards

Distance between F(-3, -8) and G(3, -8) =
√((-3-3)^2+(-8+8)^2)

= 6 yards

Distance between G(3, -8) and H(10, -12) =
√((3-10)^2+(-8+12)^2)

=
√(49+16)

=
√(65)

= 8.06 ≈ 8 yards

Distance between H(10, -12) and J(10, 6) =
√((10-10)^2+(-12-6)^2)

= 18 yards

Distance between A(3, 6) and J(10, 6) =
√((10-3)^2+(6-6)^2)

= 7 yards

Since length of fence required = perimeter of the flat area

Perimeter of the given area = 8 + 12 + 6 + 4 + 6 + 6 + 8 + 18 + 7

= 75 yards

Therefore, amount of fencing required = 75 yards

User Amay Diam
by
5.3k points
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