Answer:
Amount of fencing required = 75 yards
Explanation:
Distance between the two points
and
is given by the formula,
d =
![√((x_2-x_1)^2+(y_2-y_1)^2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/j1aab9od514eyoxydxlm0fxc2m3p0n16p9.png)
Distance between A(3, 6) and B(3, -2) =
![√((3-3)^2+(6+2)^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/t4dw9dcnv0st3c6g8x1ss84o2ahcb7rxhw.png)
= 8 yards
Distance between B(3, -2) and C(-7, 4) =
![√((3+7)^2+(-2-4)^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/sz0g2vsgxs821lx67yxscm3zj2lq9u2ouw.png)
=
![√(136)](https://img.qammunity.org/2021/formulas/mathematics/high-school/bqku3lku02tu5rz31q6i2jzqsc8oxvjpgu.png)
= 11.66 ≈ 12 yards
Distance between C(-7, 4) and D(-7, -2) =
![√((-7+7)^2+(4+2)^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/pgyw4fewh0zobe8kqmctsvdv1ugxivwjpf.png)
= 6 yards
Distance between D(-7, -2) and E(-3, -2) =
![√((-7+3)^2+(-2+2)^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/6okyfrd10lwhaw8adcklfqjokadylv9qke.png)
= 4 yards
Distance between E(-3, -2) and F(-3, -8) =
![√((-3+3)^2+(-2+8)^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/9igikhac7vplml83kjl6841gcyzyj00nik.png)
= 6 yards
Distance between F(-3, -8) and G(3, -8) =
![√((-3-3)^2+(-8+8)^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/yp77yb0906vwdhnzoxntvgw7sdphocbply.png)
= 6 yards
Distance between G(3, -8) and H(10, -12) =
![√((3-10)^2+(-8+12)^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/pjypgx6mr6pebfhztjw4oj00s9hq8suz5y.png)
=
![√(49+16)](https://img.qammunity.org/2021/formulas/mathematics/high-school/4rgz2j738wwmw71ga3m4eddogbo8dke952.png)
=
![√(65)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/d3ywsyuqdx1euh3v262q1f1m4a3mlszwho.png)
= 8.06 ≈ 8 yards
Distance between H(10, -12) and J(10, 6) =
![√((10-10)^2+(-12-6)^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/40ozhlvok92xi2gxvhj2xc55ax064tg86x.png)
= 18 yards
Distance between A(3, 6) and J(10, 6) =
![√((10-3)^2+(6-6)^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/xsmh22o7hlig1styvkch8f2ow3expuhm0p.png)
= 7 yards
Since length of fence required = perimeter of the flat area
Perimeter of the given area = 8 + 12 + 6 + 4 + 6 + 6 + 8 + 18 + 7
= 75 yards
Therefore, amount of fencing required = 75 yards