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An equation of a line with a slope of - 4/5 that passes through the point (5,3)

User Jack Casas
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1 Answer

4 votes

Answer:

y = -(4/5)x + 7

Explanation:

recall that the point-slope form of a linear equation is given as

y - y₁ = m (x - x₁)

in our case, we are given

slope, m = -4/5

and a point (x₁, y₁) = (5,3)

hence we simply substitute these values into the equation

y - y₁ = m (x - x₁)

y - 3 = -(4/5) (x - 5) (we will simplify this to convert to slope-intercept form)

y - 3 = -(4/5) (x) - (-4/5)(5)

y - 3 = -(4/5)x +4 (add 3 to both sides)

y = -(4/5)x +4 +3

y = -(4/5)x + 7

User Giorgi Nakeuri
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5.2k points