Question

A ball is thrown straight up and passes point B (at a height of 56.8 m above its starting point O) in 5.8 s. What was its initial speed? The acceleration of gravity is 9.8 m/s 2 . Answer in units of m/s

Answer 1

38.2 m/s

Step-by-step explanation:

Given:

Δy = 56.8 m

a = -9.8 m/s²

t = 5.8 s

Find: v₀

Δy = v₀ t + ½ at²

56.8 m = v₀ (5.8 s) + ½ (-9.8 m/s²) (5.8 s)²

v₀ ≈ 38.2 m/s