Question

What is the distance between P(-4,3) and Q(6,1)? Round to the nearest tenth.

Answer 1

The answer is

10.2 units

Explanation:

The distance between two points can be found by using the formula

`d = \sqrt{ ({x1 - x2})^(2) + ({y1 - y2})^(2) } \\`

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

P(-4,3) and Q(6,1)

The distance between them is

`|PQ| = \sqrt{ ({ - 4 - 6})^(2) + ({3 - 1})^(2) } \\ = \sqrt{ ({ - 10})^(2) + {2}^(2) } \\ = √(100 + 4) \: \: \: \: \: \: \: \: \: \\ = √(104) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = 2 √(26) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = 10.1980390271`

We have the final answer as

10.2 units to the nearest tenth

Hope this helps you