What is the equation of a line perpendicular to 3X+6Y= -3 and passes through the points (1,-5)

asked Apr 12, 2021 101k views

4 votes

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2 votes

Answer:

Explanation:

6y = -3x - 3

y = -1/2x - 1/2

perp. 2

y + 5 = 2(x - 1)

y + 5 = 2x - 2

y = 2x - 7

Claudioz answered Apr 17, 2021

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