Question

Deanna and Lise are playing game at the arcade. Deanna started with $20 and the the game she is playing costs $0.25 each game. Lise started with $40, and her machine costs $0.75 per game. How many games will it be before they both have the same amount of money left? Make an expression the solves the problem.

Answer 1

To determine how many games it will take for Deanna and Lise to have the same amount of money left, set up an equation using their net losses per game and solve for 'g'. It will take 40 games for them to have the same amount of money left.

Step-by-step explanation:

To determine how many games it will take for Deanna and Lise to have the same amount of money left, we need to set up an equation. Let's start by determining their net loss per game by subtracting the cost of each game from their initial amount of money. For Deanna, her net loss per game is $0.25. For Lise, her net loss per game is $0.75.

Let's represent the number of games they play with the variable 'g'. To find the number of games it will take for them to have the same amount of money left, we need to set up an equation. Deanna's remaining money after 'g' games can be represented as $20 - $0.25g. Lise's remaining money after 'g' games can be represented as $40 - $0.75g.

Setting the two expressions equal to each other, we can solve for 'g':

$20 - $0.25g = $40 - $0.75g

$20 = $40 - $0.5g

$0.5g = $20

g = $20 / $0.5 = 40

Therefore, it will take 40 games before Deanna and Lise have the same amount of money left.