33.8k views
4 votes
Suppose point D is in the interior of ∠ABC

, m∠ABC=12x−110
, m∠ABD=3x+40
, and m∠DBC=2x−10
. W

User Leo Prince
by
4.0k points

1 Answer

3 votes

Answer:


ABC = 130

Explanation:

Given


ABC=12x - 110


ABD=3x+40


DBC=2x - 10

Required

Determine the measure of ABC --- Missing part of the question

First, we need to determine the value of x

Since, D is an interior of ABC, then


ABC = ABD + DBC


12x - 110 = 3x + 40 + 2x - 10

Collect Like Terms


12x - 3x - 2x = 110 + 40 - 10


7x = 140

Solve for x


x = 140/7


x = 20

Substitute 20 for x in
ABC=12x - 110


ABC = 12 * 20 - 110


ABC = 240 - 110


ABC = 130

User Derek Wang
by
4.5k points