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Find the zeroes of the polynomials 3t^2 - 7t, 2root5y^2 + y - 3root5​

1 Answer

4 votes

Answer:

7/3

Explanation:

3t^2 - 7t

T(3t-7)

T=0, 3t-7=0,.: t=7/3

The zeros are t=7/3

2root5y^2 +y-3 root 5

Pls does the root affect y tooo.

User Megan
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