Answer:320cm³
Step-by-step explanation:
20% of oxygen is present in 100% of air
xcm³ of O2 is present in 400cm³ of air
Therefore
80cm³ of O2 is present in 400cm³ of air
Vol of air remained =400-80
=320cm³ of air
2Cu+O2=>2CuO
2mol. 1mol. 2mol
160cm³. 80cm³ 160cm³
Since O2 is used up in the reaction
Vol of air remained=320cm³
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