Answer:
Badia made 20 nails
Charli made 30 nails
Siva made 60 nails
Explanation:
Let b = number of nails Badia made
Let c = number of nails Charli made
Let s = number of nails Siva made
Given:
- Charli made one and half times as many as Badia
⇒ Equation 1: c = 1.5b
Given:
- Siva made twice as many as Charli
⇒ Equation 2: s = 2c
Given:
- They all made a total of 110 nails
⇒ Equation 3: b + c + s = 110
Substitute Equation 1 into Equation 2:
⇒ s = 2(1.5b) = 3b
Substitute s = 3b and Equation 1 into Equation 3 and solve for b:
⇒ b + c + s = 110
⇒ b + 1.5b + 3b = 110
⇒ 5.5b = 110
⇒ b = 20
Substitute found value of b into Equation 1 and solve for c:
⇒ c = 1.5b
⇒ c = 1.5(20)
⇒ c = 30
Substitute found value of c into Equation 2 and solve for s:
⇒ s = 2c
⇒ s = 2(30)
⇒ s = 60
Therefore:
- Badia made 20 nails
- Charli made 30 nails
- Siva made 60 nails