Answer:
![\boxed {\tt 5.6 \ miles}](https://img.qammunity.org/2021/formulas/mathematics/high-school/yfyz2nncpf06w0cwstl8bc4jv6bly3mbcp.png)
Explanation:
Let's set up a proportion using the following setup:
![(miles)/(minutes)= (miles)/(minutes)](https://img.qammunity.org/2021/formulas/mathematics/high-school/r6vsrffykvcgpf87q36mpk4l2otbfrqh0y.png)
We know Teresa can run 7 miles in 80 minutes.
![(7 \ miles)/(80 \ minutes)=(miles)/(minutes)](https://img.qammunity.org/2021/formulas/mathematics/high-school/uxonp1qn5k4yk3n4ekwblkn6jinb1xiuea.png)
We don't know how many miles she can run in 64 minutes. Therefore, she can run x miles in 64 minutes.
![(7 \ miles)/(80 \ minutes)=(x \ miles)/(64 \ minutes)](https://img.qammunity.org/2021/formulas/mathematics/high-school/7sx5nx6vjljpx06xtj0eesh7io6v6txmez.png)
![(7)/(80) =(x)/(64)](https://img.qammunity.org/2021/formulas/mathematics/high-school/zzabppt8x1q3jyw8ooficuwdbwceo6knji.png)
We want to solve for x ( miles in 64 minutes). We must isolate x on one side of the proportion. x is being divided by 64 and the inverse of division is multiplication. Multiply both sides of the equation by 64.
![64*(7)/(80) =(x)/(64)*64](https://img.qammunity.org/2021/formulas/mathematics/high-school/khh0iioppnhaupz6z9a1juq9otthakuuh7.png)
![64*(7)/(80) =x](https://img.qammunity.org/2021/formulas/mathematics/high-school/hrz3x41pu3lq1tazs2w9vveqdqeura279c.png)
![64*0.0875=x](https://img.qammunity.org/2021/formulas/mathematics/college/codhv6zrw65udty927sykizvmfv9np73s7.png)
![5.6=x](https://img.qammunity.org/2021/formulas/mathematics/college/oj5q0mxgk82yro0fgykqfycqt8vl3hcwov.png)
x= 5.6 miles
Teresa can run 5.6 miles in 64 minutes.