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40 votes
40 votes
100 POINTS!!! VERY URGENT

100 POINTS!!! VERY URGENT-example-1
User Emperor XLII
by
2.6k points

2 Answers

15 votes
15 votes

Answer:

D) (f o g)(x) = 10x² - 60x + 93

Explanation:

f(x) = 10x² + 3

g(x) = x - 3

⇒ (f o g)(x)

⇒ f(x - 3)

⇒ f(x - 3) = 10(x - 3)² + 3

⇒ f(x - 3) = 10(x² - 6x + 9) + 3

⇒ f(x - 3) = 10x² - 60x + 90 + 3

(f o g)(x) = 10x² - 60x + 93

User Mike Buckbee
by
3.0k points
6 votes
6 votes

Answer:


\textsf{D)} \quad (f \circ g)(x)=10x^2-60x+93

Explanation:


\textsf{If }\:f(x)=10x^2+3\:\textsf{ and }\:g(x)=x-3\:\textsf{ then}:


\begin{aligned}(f \circ g)(x) & = f[g(x)]\\ & = f(x-3)\\& = 10(x-3)^2+3\\& = 10(x^2-6x+9)+3\\& = 10x^2-60x+90+3\\& = 10x^2-60x+93\\\end{aligned}

User Nathanchere
by
2.7k points