Answer:
B. d(B, C) = BC = |6 – 1|
D. AB + BC = AC
Explanation:
Given that:
On a number line :
Point A = - 2
Point B = 1
Point C = 6
Distance BC = d(B, C) = |6 - 1| = 5
Distance AB = |-2 - 1| = 3
AB + AC ;
AB = 3 ; AC= |-2 - 6| = 8 ; BC = |1 - 6| = 5
3 + 8 = 11
HENCE
AB + AC ≠ BC
AB + BC = AC
AC = |- 2 - 6| = 8
AB = 3 ; BC = |1 - 6| = 5
3 + 5 = 8
Hence,
AB + BC = AC