Answer:
(f+g)(2) = 1
Explanation:
Given :
f(x) = x − 3
g(x) = x² − x
Note : (f+g)(x) = f(x) + g(x)
then
(f+g)(2) = f(2) + g(2)
= (2 - 3) + (2² - 2)
= -1 + 2
= 1
another method:
(f+g)(x) = f(x) + g(x) = x − 3 + x² − x = x² - 3
then
(f+g)(2) = 2² - 3 = 4 - 3 = 1