Question

Find the third angle of a triangle with 126° and 41° as two of it's angles.

Answer 1

126+41+x(this is the third angle)=180

167+x=180
-167 -167

X=13

The third angle is 13 degrees.

Answer 2

Question -:

Find the third angle of a triangle with 126° and 41° as two of it's angles.

Explanation -:

`\star \: \small{ \rm{ In \: this \: question \: we \: are \: provided \: with }}\\ \small{\rm{ the \: two \: angles \: of \: the \: triangle}} \\ \small{\rm \: {and \: asked \: to \: calculate \: the \: third \: angle.}}`

Let us assume the third angle as x

We know,

Sum of all angles of the triangle = 180°

According To Question

`\small\bf \blue{ 126° + 41° + x° = 180°}`

→ 167° + x° = 180°

→ x = 180° - 167° = 13°

`\small\boxed{ \pink{ \frak{ x = 13°}}}`

Hence, the third angle is 13°.