![\bf Step-by-step~explanation:](https://img.qammunity.org/2021/formulas/mathematics/high-school/9xh8aaerqfym7ptpm85nunqpjn4kur85ef.png)
We have to solve these term so that they won't have powers anymore.
![\bf Step~1:](https://img.qammunity.org/2021/formulas/mathematics/high-school/sk6m9v6itpfdxnsbn4miuhdikaeddk5jy4.png)
First, we have to look at the powers on both numbers. 3 has a 4 and 2 has a 2.
![\bf Step ~2:](https://img.qammunity.org/2021/formulas/mathematics/high-school/eenz8omrgn5but7jhy0ulxwqtwsst7a2ts.png)
The small numbers on the right hand corner are called powers. When those are on any term, you have to multiply the term by itself x amount of times. Since 3 has a 4 on it, we multiply the number by itself 4 times.
![\bf 3*3=9\\9*3=27\\27*3=81](https://img.qammunity.org/2021/formulas/mathematics/high-school/gbcg8bht2xhm7owpprgsieqa1km1roytjp.png)
Our first number is 81.
![\bf 2*2=4](https://img.qammunity.org/2021/formulas/mathematics/high-school/xet4e01rgfo1o4z4qjjrud54m4sic3zeor.png)
And our second number is 4! Put those numbers back into their original form and you get your final answer.
![\large\boxed{\bf Our~final~answer:~(81)/(4) }\\\boxed {\bf Or:~20.25,~ 20(1)/(4) }](https://img.qammunity.org/2021/formulas/mathematics/high-school/39yrhs4xk5pltxdq442mvz78i1ufiw9u3q.png)